Wavelengths of {K_α } X- rays of two metals 'A' and 'B' frac{4}{{1875R

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12.Atoms

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The wavelengths of ${K_\alpha }$ $X-$ rays of two metals $'A'$ and $'B'$ $\frac{4}{{1875R}}$ and $\frac{1}{{675R}}$ respectively, where $'R'$ is Rydberg's constant. The number of elements lying between $'A'$ and $'B'$ according to their atomic numbers is

A

$3$

B

$6$

C

$5$

D

$4$

Solution

$\frac{1}{{{\lambda _{{{\rm{k}}_\alpha }}}}} = \frac{{3{\rm{R}}}}{4}{({\rm{Z}} – 1)^2}$

Standard 12

Physics

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